48d^2+72d+27=0

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Solution for 48d^2+72d+27=0 equation: 



48d^2+72d+27=0

a = 48; b = 72; c = +27;
Δ = b2-4ac
Δ = 722-4·48·27
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$d=\frac{-b}{2a}=\frac{-72}{96}=-3/4$

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